(3*t^-1/4)-t^2=0

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Solution for (3*t^-1/4)-t^2=0 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(3*t^-1)/4-t^2 = 0

3/4*t^-1-t^2 = 0

t^-1*(3/4-t^3) = 0

-1*t^3 = -3/4 // : -1

t^3 = 3/4

t^3 = 3/4 // ^ 1/3

t = (3/4)^(1/3)

1/t = 0

1*t^-1 = 0 // : 1

t^-1 = 0

t naleu017Cy do O

t = (3/4)^(1/3)

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